SQL QUERIES
1) Display the details of all employees
SQL>Select *
from emp;
2) Display the depart information from department table
SQL>select *
from dept;
3) Display the name and job for all the employees
SQL>select
ename,job from emp;
4) Display the name and salary for all the employees
SQL>select
ename,sal from emp;
5) Display the employee no and totalsalary for all the employees
SQL>select
empno,ename,sal,comm, sal+nvl(comm,0) as"total salary" from
emp
6) Display the employee name and annual salary for all
employees.
SQL>select
ename, 12*(sal+nvl(comm,0)) as "annual Sal" from emp
7) Display the names of all the employees who are working in
depart number 10.
SQL>select
emame from emp where deptno=10;
8) Display the names of all the employees who are working as
clerks and
drawing a salary
more than 3000.
SQL>select ename
from emp where job='CLERK' and sal>3000;
9) Display the employee number and name who are earning comm.
SQL>select
empno,ename from emp where comm is not null;
10) Display the employee number and name who do not earn any comm.
SQL>select empno,ename from emp where comm is null;
11) Display the names of employees who are working as
clerks,salesman or
analyst and drawing a salary more than 3000.
SQL>select ename
from emp where job='CLERK' OR JOB='SALESMAN'
OR
JOB='ANALYST' AND SAL>3000;
12) Display the names of the employees who are working in
the company for
the past 5 years;
SQL>select ename
from emp where to_char(sysdate,'YYYY')-to_char(hiredate,'YYYY')>=5;
13) Display the list of employees who have joined the
company before
30-JUN-90 or after 31-DEC-90.
a)select ename from emp where hiredate < '30-JUN-1990' or
hiredate >
'31-DEC-90';
14) Display current Date.
SQL>select sysdate from dual;
15) Display the list of all users in your database(use
catalog table).
SQL>select username from all_users;
16) Display the names of all tables from current user;
SQL>select tname from tab;
17) Display the name of the current user.
SQL>show user
18) Display the names of employees working in depart number
10 or 20 or 40
or employees working as
CLERKS,SALESMAN or ANALYST.
SQL>select ename from emp where deptno in(10,20,40) or
job
in('CLERKS','SALESMAN','ANALYST');
19) Display the names of employees whose name starts with
alaphabet S.
SQL>select ename from emp where ename like 'S%';
20) Display the Employee names for employees whose name ends
with alaphabet S.
SQL>select ename from emp where ename like '%S';
21) Display the names of employees whose names have second
alphabet A in
their names.
SQL>select ename from emp where ename like '_A%';
22) select the names of the employee whose names is exactly
five characters
in length.
SQL>select ename from emp where length(ename)=5;
23) Display the names of the employee who are not working as
MANAGERS.
SQL>select ename from emp where job not in('MANAGER');
24) Display the names of the employee who are not working as
SALESMAN OR
CLERK OR ANALYST.
SQL>select ename from emp where job not
in('SALESMAN','CLERK','ANALYST');
25) Display all rows from emp table.The system should wait
after every
screen full of informaction.
SQL>set pause on
26) Display the total number of employee working in the
company.
SQL>select count(*) from emp;
27) Display the total salary beiging paid to all employees.
SQL>select sum(sal) from emp;
28) Display the maximum salary from emp table.
SQL>select max(sal) from emp;
29) Display the minimum salary from emp table.
SQL>select min(sal) from emp;
30) Display the average salary from emp table.
SQL>select avg(sal) from emp;
31) Display the maximum salary being paid to CLERK.
SQL>select max(sal) from emp where job='CLERK';
32) Display the maximum salary being paid to depart number
20.
SQL>select max(sal) from emp where deptno=20;
33) Display the minimum salary being paid to any SALESMAN.
SQL>select min(sal) from emp where job='SALESMAN';
34) Display the average salary drawn by MANAGERS.
SQL>select avg(sal) from emp where job='MANAGER';
35) Display the total salary drawn by ANALYST working in
depart number 40.
SQL>select sum(sal) from emp where job='ANALYST' and
deptno=40;
36) Display the names of the employee in order of salary i.e
the name of
the employee earning lowest salary should salary appear first.
SQL>select ename from emp order by sal;
37) Display the names of the employee in descending order of
salary.
a)select ename from emp order by sal desc;
38) Display the names of the employee in order of employee
name.
a)select ename from emp order by ename;
39) Display empno,ename,deptno,sal sort the output first
base on name and
within name by deptno and with in deptno by sal.
SQL>select empno,ename,deptno,sal from emp order by
40) Display the name of the employee along with their annual
salary(sal*12).The name of the employee earning highest annual salary should
apper first.
SQL>select ename,sal*12 from emp order by sal desc;
41) Display name,salary,hra,pf,da,total salary for each
employee. The
output should be in the order of total salary,hra 15% of
salary,da 10% of salary,pf 5%
salary,total salary will be(salary+hra+da)-pf.
SQL>select ename,sal,sal/100*15 as hra,sal/100*5 as
pf,sal/100*10 as
da, sal+sal/100*15+sal/100*10-sal/100*5 as total from emp;
42) Display depart numbers and total number of employees
working in each
department.
SQL>select deptno,count(deptno)from emp group by deptno;
43) Display the various jobs and total number of employees
within each job
group.
SQL>select job,count(job)from emp group by job;
44) Display the depart numbers and total salary for each
department.
SQL>select deptno,sum(sal) from emp group by deptno;
45) Display the depart numbers and max salary for each
department.
SQL>select deptno,max(sal) from emp group by deptno;
46) Display the various jobs and total salary for each job
SQL>select job,sum(sal) from emp group by job;
47) Display the various jobs and total salary for each job
SQL>select job,min(sal) from emp group by job;
48) Display the depart numbers with more than three
employees in each dept.
SQL>select deptno,count(deptno) from emp group by deptno
having
count(*)>3;
49) Display the various jobs along with total salary for
each of the jobs
where total salary is greater than 40000.
SQL>select job,sum(sal) from emp group by job having
sum(sal)>40000;
50) Display the various jobs along with total number of
employees in each
job.The output should contain only those jobs with more than three employees.
SQL>select job,count(empno) from emp group by job having
count(job)>3
51) Display the name of the empployee who earns highest
salary.
SQL>select ename from emp where sal=(select max(sal) from
emp);
52) Display the employee number and name for employee
working as clerk and
earning highest salary among clerks.
SQL>select empno,ename from emp where where job='CLERK'
and
sal=(select max(sal) from emp where
job='CLERK');
53) Display the names of salesman who earns a salary more
than the highest
salary of any clerk.
SQL>select ename,sal from emp where job='SALESMAN' and
sal>(select
max(sal) from emp
where job='CLERK');
54) Display the names of clerks who earn a salary more than
the lowest
salary of any salesman.
SQL>select ename from emp where job='CLERK' and
sal>(select min(sal)
from emp
where
job='SALESMAN');
Display the names of employees who earn a salary more than
that of
Jones or that of salary grether than that of scott.
SQL>select ename,sal from emp where sal>
(select sal from emp where ename='JONES')and sal> (select
sal from emp
where ename='SCOTT');
55) Display the names of the employees who earn highest
salary in their
respective departments.
SQL>select ename,sal,deptno from emp where sal in(select
max(sal) from
emp group by deptno);
56) Display the names of the employees who earn highest
salaries in their
respective job groups.
SQL>select ename,sal,job from emp where sal in(select
max(sal) from emp
group by job)
57) Display the employee names who are working in accounting
department.
SQL>select ename from emp where deptno=(select deptno
from dept where
dname='ACCOUNTING')
58) Display the employee names who are working in Chicago.
SQL>select ename from emp where deptno=(select deptno
from dept where
LOC='CHICAGO')
59) Display the Job groups having total salary greater than
the maximum
salary for managers.
SQL>SELECT JOB,SUM(SAL) FROM EMP GROUP BY JOB HAVING
SUM(SAL)>(SELECT
MAX(SAL) FROM EMP WHERE JOB='MANAGER');
60) Display the names of employees from department number 10
with salary
grether than that of any employee working in other
department.
SQL>select ename from emp where deptno=10 and
sal>any(select sal from
emp where deptno not in 10).
61) Display the names of the employees from department
number 10 with
salary greater than that of all employee working in other
departments.
SQL>select ename from emp where deptno=10 and
sal>all(select sal from
emp where deptno not in 10).
62) Display the names of the employees in Uppercase.
SQL>select upper(ename)from emp
63) Display the names of the employees in Lowecase.
SQL>select lower(ename)from emp
64) Display the names of the employees in Propercase.
SQL>select initcap(ename)from emp;
65) Display the length of Your name using appropriate
function.
SQL>select length('name') from dual
66) Display the length of all the employee names.
SQL>select length(ename) from emp;
67) select name of the employee concatenate with employee
number.
SQL>select ename||empno from emp;
68) User appropriate function and extract 3 characters
starting from 2
characters from the following string 'Oracle'. i.e the out put should be
'ac'.
SQL>select substr('oracle',3,2) from dual
69) Find the First occurance of character 'a' from the
following string i.e
'Computer Maintenance Corporation'.
SQL>SELECT INSTR('Computer Maintenance
Corporation','a',1) FROM DUAL
70) Replace every occurance of alphabhet A with B in the
string Allens(use
translate function)
SQL>select translate('Allens','A','B') from dual
71) Display the informaction from emp table.Where job
manager is found it
should be displayed as boos(Use replace function).
SQL>select replace(JOB,'MANAGER','BOSS') FROM EMP;
72) Display empno,ename,deptno from emp table.Instead of
display department
numbers display the related department name(Use decode
function).
SQL>select empno,ename,decode(deptno,10,'ACCOUNTING',20,'RESEARCH',30,'SALES',40,'OPRATIONS')
from emp;
73) Display your age in days.
SQL>select to_date(sysdate)-to_date('10-sep-77')from dual
74) Display your age in months.
SQL>select months_between(sysdate,'10-sep-77') from dual
75) Display the current date as 15th Augest Friday Nineteen
Ninety Saven.
SQL>select to_char(sysdate,'ddth Month day year') from
dual
76) Display the following output for each row from emp
table.
scott has joined the company on wednesday 13th August ninten
nintey.
SQL>select ENAME||' HAS JOINED THE COMPANY ON '||to_char(HIREDATE,'day
ddth Month
year') from EMP;
77) Find the date for nearest saturday after current date.
SQL>SELECT NEXT_DAY(SYSDATE,'SATURDAY')FROM DUAL;
78) Display current time.
SQL>select to_char(sysdate,'hh:MM:ss') from dual.
79) Display the date three months Before the current date.
SQL>select add_months(sysdate,3) from dual;
80) Display the common jobs from department number 10 and
20.
SQL>select job from emp where deptno=10 and job in(select
job from emp
where deptno=20);
81) Display the jobs found in department 10 and 20 Eliminate
duplicate jobs.
SQL>select distinct(job) from emp where deptno=10 or
deptno=20
(or)
SQL>select distinct(job) from emp where deptno in(10,20);
82) Display the jobs which are unique to department 10.
SQL>select distinct(job) from emp where deptno=10
83) Display the details of those who do not have any person
working under them.
SQL>select e.ename from emp,emp e where emp.mgr=e.empno
group by
e.ename having count(*)=1;
84) Display the details of those employees who are in sales
department and
grade is 3.
SQL>select * from emp where deptno=(select deptno from
dept where
dname='SALES')and sal between(select losal from salgrade
where grade=3)and
(select
hisal from salgrade where grade=3);
85) Display those who are not managers and who are managers
any one.
i)display the managers names
SQL>select distinct(m.ename) from emp e,emp m where
m.empno=e.mgr;
ii)display the who are not managers
SQL>select ename from emp where ename not in(select
distinct(m.ename)
from emp
e,emp m where m.empno=e.mgr);
86) Display those employee whose name contains not less than
4 characters.
SQL>select ename from emp where length(ename)>4;
87) Display those department whose name start with
"S" while the location
name ends with "K".
SQL>select dname from dept where dname like 'S%' and loc
like '%K';
88) Display those employees whose manager name is JONES.
SQL>select p.ename from emp e,emp p where e.empno=p.mgr
and
e.ename='JONES';
89) Display those employees whose salary is more than 3000
after giving 20%
increment.
SQL>select ename,sal from emp where (sal+sal*.2)>3000;
90) Display all employees while their dept names;
SQL>select ename,dname from emp,dept where emp.deptno=dept.deptno
91) Display ename who are working in sales dept.
SQL>select ename from emp where deptno=(select deptno
from dept where
dname='SALES');
92) Display employee name,deptname,salary and comm for those
sal in between
2000 to 5000 while location is chicago.
SQL>select ename,dname,sal,comm from emp,dept where
sal between 2000
and 5000
and loc='CHICAGO' and
emp.deptno=dept.deptno;
93)Display those employees whose salary greter than his
manager salary.
SQL>select p.ename from emp e,emp p where e.empno=p.mgr
and p.sal>e.sal
94) Display those employees who are working in the same dept
where his
manager is work.
SQL>select p.ename from emp e,emp p where e.empno=p.mgr
and
p.deptno=e.deptno;
95) Display those employees who are not working under any
manager.
SQL>select ename from emp where mgr is null
96) Display grade and employees name for the dept no 10 or
30 but grade is
not 4 while joined the company before 31-dec-82.
SQL>select ename,grade from emp,salgrade where sal
between losal and
hisal and deptno in(10,30) and grade<>4 and
hiredate<'31-DEC-82';
97) Update the salary of each employee by 10% increment who
are not
eligiblw for commission.
SQL>update emp set sal=sal+sal*10/100 where comm is null;
98) SELECT those employee who joined the company before
31-dec-82 while
their dept location is newyork or Chicago.
SQL>SELECT EMPNO,ENAME,HIREDATE,DNAME,LOC FROM EMP,DEPT
WHERE
(EMP.DEPTNO=DEPT.DEPTNO)AND
HIREDATE <'31-DEC-82' AND DEPT.LOC IN('CHICAGO','NEW YORK');
99) DISPLAY EMPLOYEE NAME,JOB,DEPARTMENT,LOCATION FOR ALL
WHO ARE WORKING
AS MANAGER?
SQL>select ename,JOB,DNAME,LOCATION from emp,DEPT where
mgr is not
null;
100) DISPLAY THOSE EMPLOYEES WHOSE MANAGER NAME IS JONES? --
[AND ALSO
DISPLAY THEIR MANAGER NAME]?
SQL> SELECT P.ENAME FROM EMP E, EMP P WHERE E.EMPNO=P.MGR
AND
E.ENAME='JONES';
101) Display name and salary of ford if his salary is equal
to hisal of his
grade
a)select ename,sal,grade from emp,salgrade where sal between
losal and
hisal
and ename ='FORD' AND
HISAL=SAL;
102) Display employee name,job,depart name ,manager name,his
grade and make
out an under department wise?
SQL>SELECT E.ENAME,E.JOB,DNAME,EMP.ENAME,GRADE FROM
EMP,EMP
E,SALGRADE,DEPT
WHERE EMP.SAL BETWEEN LOSAL AND HISAL AND EMP.EMPNO=E.MGR
AND
EMP.DEPTNO=DEPT.DEPTNO ORDER BY DNAME
103) List out all employees name,job,salary,grade and depart
name for every
one in the company except
'CLERK'.Sort on salary display the highest salary?
SQL>SELECT ENAME,JOB,DNAME,SAL,GRADE FROM EMP,SALGRADE,DEPT
WHERE
SAL BETWEEN LOSAL AND HISAL AND EMP.DEPTNO=DEPT.DEPTNO AND
JOB
NOT IN('CLERK')ORDER
BY SAL ASC;
104) Display the employee name,job and his manager.Display
also employee who
are without manager?
SQL>select e.ename,e.job,eMP.ename AS Manager from
emp,emp e where
emp.empno(+)=e.mgr
105) Find out the top 5 earners of company?
SQL>SELECT DISTINCT SAL FROM EMP E WHERE 5>=(SELECT
COUNT(DISTINCT SAL)
FROM
EMP A WHERE
A.SAL>=E.SAL)ORDER BY SAL DESC;
106) Display name of those employee who are getting the
highest salary?
SQL>select ename from emp where sal=(select max(sal) from
emp);
107) Display those employee whose salary is equal to average
of maximum and
minimum?
SQL>select ename from emp where sal=(select max(sal)+min(sal)/2
from
emp);
108) Select count of employee in each department where count greater than 3?
SQL>select count(*) from emp group by deptno having
count(deptno)>3
109) Display dname where at least 3 are working and display
only department
name?
SQL>select distinct d.dname from dept d,emp e where
d.deptno=e.deptno
and 3>any
(select
count(deptno) from emp group by deptno)
110) Display name of those managers name whose salary is
more than average
salary of his company?
SQL>SELECT E.ENAME,EMP.ENAME FROM EMP,EMP E
WHERE
EMP.EMPNO=E.MGR AND E.SAL>(SELECT AVG(SAL) FROM EMP);
111)Display those managers name whose salary is more than
average salary of
his employee?
SQL>SELECT DISTINCT EMP.ENAME FROM EMP,EMP E WHERE
E.SAL <(SELECT
AVG(EMP.SAL) FROM EMP
WHERE
EMP.EMPNO=E.MGR GROUP BY EMP.ENAME) AND
EMP.EMPNO=E.MGR;
112) Display employee name,sal,comm and net pay for those
employee
whose net pay is greter than or equal to any other employee
salary of
the company?
SQL>select ename,sal,comm,sal+nvl(comm,0) as NetPay from
emp
where
sal+nvl(comm,0) >any (select sal from emp)
113) Display all employees names with total sal of company
with each
employee name?
SQL>SELECT ENAME,(SELECT SUM(SAL) FROM EMP) FROM EMP;
114) Find out last 5(least)earners of the company.?
SQL>SELECT DISTINCT SAL FROM EMP E WHERE
5>=(SELECT COUNT(DISTINCT SAL) FROM EMP A WHERE
A.SAL<=E.SAL)
ORDER BY
SAL DESC;
115) Find out the number of employees whose salary is
greater than their
manager salary?
SQL>SELECT E.ENAME FROM EMP ,EMP E WHERE EMP.EMPNO=E.MGR
AND
EMP.SAL
116) Display those department where no employee working?
SQL>select dname from emp,dept where emp.deptno not
in(emp.deptno)
117) Display those employee whose salary is ODD value?
SQL>select * from emp where sal<0 span="">
118) Display those employee whose salary contains alleast 3
digits?
SQL>select * from emp where length(sal)>=3;
119) Display those employee who joined in the company in the
month of Dec?
SQL>select ename from emp where
to_char(hiredate,'MON')='DEC';
120) Display those employees whose name contains
"A"?
SQL>select ename from emp where instr(ename,'A')>0;
or
SQL>select ename from emp where ename like('%A%');
121) Display those employee whose deptno is available in
salary?
SQL>select emp.ename from emp, emp e where
emp.sal=e.deptno;
122) Display those employee whose first 2 characters from
hiredate -last 2
characters of salary?
SQL>select ename,SUBSTR(hiredate,1,2)||ENAME||substr(sal,-2,2)
from emp
123) Display those employee whose 10% of salary is equal to
the year of
joining?
SQL>select ename from emp where
to_char(hiredate,'YY')=sal*0.1;
124) Display those employee who are working in sales or
research?
SQL>SELECT ENAME FROM EMP WHERE DEPTNO IN(SELECT DEPTNO
FROM DEPT WHERE
DNAME
IN('SALES','RESEARCH'));
125) Display the grade of jones?
SQL>SELECT ENAME,GRADE FROM EMP,SALGRADE
WHERE SAL
BETWEEN LOSAL AND HISAL AND Ename='JONES';
126) Display those employees who joined the company before
15 of the month?
a)select ename from emp where to_char(hiredate,'DD')<15 span="">
127) Display those employee who has joined before 15th of
the month.
a)select ename from emp where to_char(hiredate,'DD')<15 span="">
128) Delete those records where no of employees in a
particular department
is less than 3.
SQL>delete from emp where deptno=(select deptno from emp
group by
deptno having count(deptno)<3 span="">
129) Display the name of the department where no employee
working.
SQL> SELECT E.ENAME,E.JOB,M.ENAME,M.JOB FROM EMP E,EMP M
WHERE E.MGR=M.EMPNO
130) Display those employees who are working as manager.
SQL>SELECT M.ENAME MANAGER FROM EMP M ,EMP E
WHERE E.MGR=M.EMPNO GROUP BY M.ENAME
131) Display those employees whose grade is equal to any
number of sal but
not equal to first number of sal?
SQL> SELECT ENAME,GRADE FROM EMP,SALGRADE
WHERE
GRADE NOT IN(SELECT SUBSTR(SAL,0,1)FROM EMP)
132) Print the details of all the employees who are
Sub-ordinate to BLAKE?
SQL>select emp.ename from emp, emp e where
emp.mgr=e.empno and
e.ename='BLAKE';
133) Display employee name and his salary whose salary is
greater than
highest average of
department number?
SQL>SELECT SAL FROM EMP WHERE SAL>(SELECT MAX(AVG(SAL))
FROM EMP
GROUP BY
DEPTNO);
134) Display the 10th record of emp table(without using
rowid)
SQL>SELECT * FROM EMP WHERE ROWNUM<11 span="">
MINUS
SELECT *
FROM EMP WHERE ROWNUM<10 span="">
135) Display the half of the ename's in upper case and
remaining lowercase?
SQL>SELECT
SUBSTR(LOWER(ENAME),1,3)||SUBSTR(UPPER(ENAME),3,LENGTH(ENAME))
FROM EMP;
136) Display the 10th record of emp table without using
group by and rowid?
SQL>SELECT * FROM EMP WHERE ROWNUM<11 span="">
MINUS
SELECT *
FROM EMP WHERE ROWNUM<10 span="">
Delete the
10th record of emp table.
SQL>DELETE FROM EMP WHERE EMPNO=(SELECT EMPNO FROM EMP
WHERE ROWNUM<11 span="">
MINUS
SELECT
EMPNO FROM EMP WHERE ROWNUM<10 span="">
137) Create a copy of emp table;
SQL>create table new_table as select * from emp where
1=2;
138) Select ename if ename exists more than once.
SQL>select ename
from emp e group by ename having count(*)>1;
139) Display all enames in reverse order?(SMITH:HTIMS).
SQL>SELECT REVERSE(ENAME)FROM EMP;
140) Display those employee whose joining of month and grade
is equal.
SQL>SELECT ENAME FROM EMP WHERE SAL BETWEEN
(SELECT
LOSAL FROM SALGRADE WHERE
GRADE=TO_CHAR(HIREDATE,'MM')) AND
(SELECT HISAL
FROM SALGRADE WHERE
GRADE=TO_CHAR(HIREDATE,'MM'));
141) Display those employee whose joining DATE is available
in deptno.
SQL>SELECT ENAME FROM EMP WHERE
TO_CHAR(HIREDATE,'DD')=DEPTNO
142) Display those employees name as follows
A ALLEN
B BLAKE
SQL> SELECT SUBSTR(ENAME,1,1),ENAME FROM EMP;
143) List out the employees ename,sal,PF(20% OF SAL) from
emp;
SQL>SELECT ENAME,SAL,SAL*.2 AS PF FROM EMP;
144) Create table emp with only one column empno;
SQL>Create table emp as select empno from emp where 1=2;
145) Add this column to emp table ename vrachar2(20).
SQL>alter table emp add(ename varchar2(20));
146) Oops I forgot give the primary key constraint. Add in now.
SQL>alter table emp add primary key(empno);
147) Now increase the length of ename column to 30
characters.
SQL>alter table emp modify(ename varchar2(30));
148) Add salary column to emp table.
SQL>alter table emp add(sal number(10));
149) I want to give a validation saying that salary cannot
be greater 10,000
(note give a name to this constraint)
SQL>alter table emp add constraint chk_001
check(sal<=10000)
150) For the time being I have decided that I will not
impose this validation.My boss has agreed to pay more than 10,000.
SQL>again alter the table or drop constraint with alter table emp drop constraint chk_001
(or)Disable the constraint by using alter
table emp modify constraint chk_001 disable;
151) My boss has changed his mind. Now he doesn't want to pay more than
10,000.so revoke that salary constraint.
SQL>alter table emp modify constraint chk_001 enable;
152) Add column called as mgr to your emp table;
SQL>alter table emp add(mgr number(5));
153) Oh! This column should be related to empno. Give a command to add this
constraint.
SQL>ALTER TABLE EMP ADD CONSTRAINT MGR_DEPT FOREIGN
KEY(MGR) REFERENCES
EMP(EMPNO)
154) Add deptno column to your emp table;
SQL>alter table emp add(deptno number(5));
155) This deptno column should be related to deptno column
of dept table;
SQL>alter table emp add constraint dept_001 foreign
key(deptno)
reference dept(deptno)
[deptno
should be primary key]
156) Give the command to add the constraint.
SQL>alter table
157) Create table called as newemp. Using single command create this table
as well as get data into this table(use create table as);
SQL>create table newemp as select * from emp;
SQL>Create table called as newemp. This table should contain only
empno,ename,dname.
SQL>create table newemp as select empno,ename,dname from
emp,dept where
1=2;
158) Delete the rows of employees who are working in the
company for more
than 2 years.
SQL>delete from emp where (sysdate-hiredate)/365>2;
159) Provide a commission(10% Comm Of Sal) to employees who
are not earning
any commission.
SQL>select sal*0.1 from emp where comm is null
160) If any employee has commission his commission should be
incremented by
10% of his salary.
SQL>update emp set comm=sal*.1 where comm is not null;
161) Display employee name and department name for each
employee.
SQL>select empno,dname from emp,dept where
emp.deptno=dept.deptno
162)Display employee number,name and location of the
department in which he
is working.
SQL>select empno,ename,loc,dname from emp,dept where
emp.deptno=dept.deptno;
163) Display ename,dname even if there are no employees
working in a
particular department(use outer join).
SQL>select ename,dname from emp,dept where
emp.deptno=dept.deptno(+)
164) Display employee name and his manager name.
SQL>select p.ename,e.ename from emp e,emp p where e.empno=p.mgr;
165) Display the department name and total number of
employees in each
department.
SQL>select dname,count(ename) from emp,dept where
emp.deptno=dept.deptno group by dname;
166)Display the department name along with total salary in
each department.
SQL>select dname,sum(sal) from emp,dept where
emp.deptno=dept.deptno
group by dname;
167) Display itemname and total sales amount for each item.
SQL>select itemname,sum(amount) from item group by
itemname;
168) Write a Query To Delete The Repeted Rows from emp
table;
SQL>Delete from emp where rowid not in(select
min(rowid)from emp group
by ename)
169) TO DISPLAY 5 TO 7 ROWS FROM A TABLE
SQL>select ename from emp
where rowid
in(select rowid from emp where rownum<=7
minus
select rowid from
empi where rownum<5 span="">
170) DISPLAY TOP N ROWS FROM TABLE?
SQL>SELECT * FROM
(SELECT
* FROM EMP ORDER BY ENAME DESC)
WHERE ROWNUM <10 span="">
171) DISPLAY TOP 3
SALARIES FROM EMP;
SQL>SELECT SAL FROM ( SELECT * FROM EMP ORDER BY SAL DESC )
WHERE ROWNUM <4 span="">
172) DISPLAY 9th FROM
THE EMP TABLE?
SQL>SELECT ENAME FROM EMP
WHERE ROWID=(SELECT ROWID FROM EMP
WHERE ROWNUM<=10
MINUS
SELECT ROWID FROM EMP WHERE ROWNUM
<10 span="">
select
second max salary from emp;
select
max(sal) fromemp where sal<(select
max(sal) from emp);
